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Question
Class 12ChemistryElectrochemistry

Write the Nernst equation and calculate the e.m.f. of the following cells at 298  K.

(i) Mg (s) | Mg2+ (0.001 M) | | Cu2+ (0.001 M) | Cu (s)           

(ii) Fe (s) | Fe2+ (0.001 M) | | H+ (1 M) | H2 (g) (1 bar) | Pt (s)

(iii) Sn (s) | Sn2+ (0.050 M) | | H+ (0.020 M) | H2 (g) (1 bar) | Pt (s)

(iv) Pt (s) | Br2 (l) | Br (0.010 M) | | H+ (0.030 M) | H2 (g) (1 bar) | Pt (s)

Given EºMg2+/Mg = 2.37 V, EºCu2+/Cu = +0.34 V, EºFe2+ Fe = – 0.44 V, EºSn2+/Sn = – 0.14 V, Eº1/2 Br2/ Br– = + 1.08 V.

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Write the Nernst equation and calculate the e.m.f. of the following cells at 298  K.(i) Mg (s) | Mg2+ (0.001 M) | | Cu2+ (0.001 M) | Cu (s)           (ii) Fe (s) | Fe2+ (0.001 M) | | H+ (1 M) | H2 (g) (1 bar) | Pt (s)(iii) Sn (s) | Sn2+ (0.050 M) | | H+ (0.020 M) | H2 (g) (1 bar) | Pt (s)(iv) Pt (s) | Br2 (l) | Br– (0.010 M) | | H+ (0.030 M) | H2 (g) (1 bar) | Pt (s)Given EºMg2+/Mg = 2.37 V, EºCu2+/Cu = +0.34 V, EºFe2+ Fe = – 0.44 V, EºSn2+/Sn = – 0.14 V, Eº1/2 Br2/ Br– = + 1.08 V. | Shiksha Nation