What is the oxidation number of metals in:
(i) [Fe(CN)6]4−
(ii) MnO4−
(i) Fe in [Fe(CN)6]4−
Let the oxidation number of Fe = x.
x + 6(−1) = −4 ⟶ x − 6 = −4 ⟶ x = +2
Thus, the oxidation number of Fe in [Fe(CN)6]4− is +2.
(ii) Mn in MnO4−
Let the oxidation number of Mn = x.
x + 4(−2) = −1 ⟶ x − 8 = −1 ⟶ x = +7
Thus, the oxidation number of Mn in MnO4− is +7.