Two moles of an ideal gas initially at 27°C and one atmospheric pressure are compressed isothermally and reversibly till the final pressure of the gas is 10 atm. Calculate q, w and ∆V fro the process. 

Here, n = 2 moles, T = 27°C = 300 K, P₁ = 1 atm, P₂ = 10 atm

w = 2.303nRT logP₂/P₁ = 2.303 × 2 × 8.314 JK⁻¹ mol⁻¹ × 300K × log10/1 = 11488 J 

For isothermal compression of ideal gas, ΔU = 0

Further, ΔU = q + w   

∴   q = −w = −11488 J.