The two equal sides of an isosceles triangle with fixed base b are decreasing at the rate of 3 cm per second. How fast is the area decreasing when the two equal sides are equal to the base?
Let ΔABC be isosceles where BC is the base of fixed length b. Let the length of the two equal sides of ΔABC be a. Draw AD⊥BC.
Now, in ΔADC, by applying the Pythagoras theorem, we have:

