The sum of three consecutive multiples of 2 is 18. Find the numbers.

Let the three consecutive multiples of 2 be 2x, 2x + 2 and 2x + 4.

As per the conditions of the question, we have

2x + (2x + 2) + (2x + 4) = 18

⇒ 2x + 2x + 2 + 2x + 4 = 18

⇒ 6x + 6 = 18

⇒ 6x = 18 – 6 (Transposing 6 to RHS)

⇒ 6x = 12

⇒ x = 2

Thus, the required multiples are

2 × 2 = 4, 4 + 2 = 6, 6 + 2 = 8 i.e., 4, 6 and 8.