The Ha -line of the Balmer series is obtained from the transition n = 3 (energy = – 1.5 eV) to n = 2 (energy = – 3.4 eV). Calculate the wave length of this line. Given that h = 6.6 × 10-34 Js; 1eV = 1.6 × 10–19 J and c = 3 × 108 ms–1.

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Shiksha Nation · Accepted Answer

Here,   h = 6.6 × 10-34Js; 1eV = 1.6 × 10–19Jand 3 × 108 m s–1 Energy of n = 2 level, E2 = -3.4 eVEnergy of n = 3 level, E3 = -1.5 eVTherefore, energy of the photon emitted during transition from n = 3 to n = 2 level, hv = E3 – E2 = -1.5 – (-3.4) = 1.9 eV

The H_a -line of the Balmer series is obtained from the transition n = 3 (energy = – 1.5 eV) to n = 2 (energy = – 3.4 eV). Calculate the wave length of this line. Given that h = 6.6 × 10^-34 Js; 1eV = 1.6 × 10^–19 J and c = 3 × 10⁸ ms^–1.

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