Question
Class 7MathematicsIntegers Class 7
The given table shows the freezing points in °F of different gases at sea level. Convert each of these into °C to the nearest integral value using the relation:
C = 5/9 (F − 32)
| Gas | Freezing point at sea level (°F) | Freezing point at sea level (°C) |
|---|---|---|
| Hydrogen | -435 | |
| Krypton | -251 | |
| Oxygen | -369 |
Verified Answer
Freezing point of Hydrogen = -435°F
C = [-435 – 32]
= [-467]
= 5 × (-51.9)
= 259.5°C or 259°C
For Krypton, freezing point = -251°F
C = [-251 – 32]
= [-283]
= 5 × (-31.4)]
= -157°C
For Oxygen, freezing point = -369°F
C = [-369 – 32]
= [-401]
= 5 × (44.56)
= 222.80° C or 223°C
Hence, the required freezing points at sea level in °C for Hydrogen = -259°C, Krypton = -157°C, Oxygen = -223°C