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Prove that: (tan(A + B)) / (cot(A - B)) = (tan2A - tan2B) / (1 - tan2A × tan2B)
(tan(A + B)) / (cot(A - B)) = tan(A + B) tan(A - B)
= ((tan A + tan B) / (1 - tan A tan B)) × ((tan A - tan B) / (1 + tan A tan B))
= (tan2A - tan2B) / (1 - tan2A tan2B)