Predict reaction of 1N sulphuric acid with the following metals:

(i) Copper
E°(Cu²⁺/Cu) = +0.34 V

(ii) Lead
E°(Pb²⁺/Pb) = −0.13 V

(iii) Iron
E°(Fe²⁺/Fe) = −0.44 V

(i) Since E°(Cu²⁺/Cu) = +0.34 V is higher than E°(H⁺/H₂) = 0.0 V, therefore copper will not react with 1N H₂SO₄ to produce H₂ gas.

(ii) Since E°(Pb²⁺/Pb) = −0.13 V and E°(H⁺/H₂) = 0.0 V, therefore lead will react with 1N H₂SO₄ to produce H₂ gas.

(iii) Since E°(Fe²⁺/Fe) = −0.44 V and E°(H⁺/H₂) = 0.0 V, therefore iron will react with 1N H₂SO₄ to produce H₂ gas.