Observe the figure and state the three pairs of equal parts in triangles ABC and DCB.

(i) Is ΔABC = ΔDCB? Why?

(ii) Is AB = DC? Why?

(iii) Is AC = DB? Why?

(i) In ΔABC and ΔDCB

∠ABC = ∠DCB = 70° (40° + 30° = 70°) (Given)

∠ACB = ∠DCB = 30° (Given)

BC = CB (Common)

ΔABC = ΔDCB (By ASA rule)

(ii) Yes,

AB = DC (Congruent parts of congruent triangles)

(iii) Yes,

AC = DB (Congruent parts of congruent triangles)