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In the given figure, PQ || RS and PQ = RS. Prove that ΔPUQ = ΔSUR.

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In ΔPUQ and ΔSUR

PQ = SR = 4 cm

∠UPQ = ∠USR (Alternate interior angles)

∠PQU = ∠SRU (Alternate interior angles)

ΔPUQ = ΔSUR (By ASA rule)

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