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In the given figure, AP = BQ, PR = QS. Show that ΔAPS = ΔBQR

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In ΔAPS and ΔBQR

AP = BQ (Given)

PR = QS (Given)

PR + RS = QS + RS (Adding RS to both sides)

PS = QR

∠APS = ∠BQR = 90° (Given)

ΔAPS = ΔBQR (by SAS rule)

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