If (1 - i) is a root of the equation x2 + ax + b = 0, where a, b ∈ ℝ, then find the values of a and b.
Sum of roots -a/1= (1 - i) + (1 + i) = -2
But sum of roots = -a ⇒ -a = 2 ⇒ a = -2
Product of roots b/1 = (1 - i)(1 + i) = 1 - i2 = 1 + 1 = 2
But product of roots = b ⇒ b = 2
Therefore, a = -2 and b = 2