For two reactions:

K₁ = 10⁶e^−30000/T
K₂ = 10⁴e^−24000/T

Find temperature where both rate constants are equal.

Solution:

At equal rate constants:

10⁶e^−30000/T = 10⁴e^−24000/T

10² = e^6000/T

Taking logarithm:

2 ln10 = 6000/T

T = 6000 / (2 × 2.303)

T ≈ 1303 K

Correct Answer: 1303 K