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The total number of terms in (x + 1/x)¹² will be 13, so the middle term will be the seventh.

Therefore,

T₇ = ¹²C₆(x)¹²⁻⁶(1/x)⁶

= ¹²C₆(x⁶)(1/x⁶) = ¹²C₆

Hence, the seventh term will be constant and its value will be ¹²C₆.

"}}]}]]}]

Find the term in the expansion of (x + 1/x)12 which will be constant.

Verified Answer

Find the term in the expansion of (x + 1/x)¹² which will be constant.