Find the greatest number which divides 82 and 132 leaving 1 and 6, respectively as remainders.

Given numbers are 82 and 132 and the remainders are 1 and 6 respectively.

We have, 82 – 1 = 81 and 132 – 6 = 126

So, we need to find the HCF of 81 and 126

Common factor is 3 (occurring twice).

∴ HCF = 3 × 3 = 9