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Here R = 6400 km; x = 16 km

g' = g (1 − ^x/_R)

= g (1 − ¹⁶/₆₄₀₀)

= ³⁹⁹/₄₀₀ g

∴ g − g' = g − ³⁹⁹/₄₀₀ g = 2.5 × 10^-3 g

Decrease in weight of the body = ^{mg − mg'}/_mg × 100

= ^{g − g'}/_g × 100

= ^{2.5 × 10-3}/_g × g × 100

= 0.25%

"}}]}]]}]

Find the % decrease in weight of a body, when taken 16 km below the surface of earth. Take radius of earth = 6400 km.

Verified Answer