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Determines:
(a) |5| – |- 3|
(b) |5 – 6|+ |-1|
(c) – 7 + |– 3|
(d) |5| + |– 12|
(a) | 5 | – | – 3 | = 5 – 3 = 2 [∵ |a| = a and |- a| = a]
(b) |5 – 6 | + |- 1| = |- 1| + |-1| = 1 + 1 = 2
(c) – 7 + |– 3| = -7 + 3 = -4
(d) |5| + |– 12| = 5 + 12 = 17