Construct a ΔPQR in which m∠P = 60° and m∠Q = 30°, QR = 4.8 cm.

Steps of construction:

(i) Draw QR = 4.8 cm.

(ii) Draw ∠Q = 30°.

(iii) Draw ∠R = 90° which meets the former angle line at P.

(iv) ∠P = 180° – (30° + 90°) = 60°

(v) ΔPQR is the required triangle.