UnlockX Scholarship Test — India’s most honest scholarship test. Register now.
Question
Class 12ChemistryElectrochemistry

Conductivity of 0.00241 M acetic acid is 7.896 × 10–5 S cm–1. Calculate its molar conductivity and if ∧° for acetic acid is 390.5S cm2 mol–1, what is its dissociation constant?

Verified Answer

Uploaded image
Conductivity of 0.00241 M acetic acid is 7.896 × 10–5 S cm–1. Calculate its molar conductivity and if ∧° for acetic acid is 390.5S cm2 mol–1, what is its dissociation constant? | Shiksha Nation