1a:["$","div",null,{"className":"p-6 md:p-8","children":["$","div",null,{"className":" prose prose-lg max-w-none break-words prose-headings:font-bold prose-headings:text-slate-900 prose-p:text-slate-700 prose-p:leading-relaxed prose-strong:text-slate-900 prose-ul:list-disc prose-ol:list-decimal prose-li:text-slate-700 mb-4 [&_table]:w-auto [&_table]:max-w-full [&_table]:border-collapse [&_th]:border [&_th]:border-slate-300 [&_th]:px-3 [&_th]:py-2 [&_th]:text-left [&_td]:border [&_td]:border-slate-200 [&_td]:px-3 [&_td]:py-2 [&_table]:my-4 overflow-x-auto","dangerouslySetInnerHTML":{"__html":"

Circuit left voltmeter = 10V, right voltmeter = 8V, 4Ω on right

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Voltage across R = 10 − 8 = 2V Current I = V across 4Ω / 4 = 8/4 = 2 A

(a) Current through R = 2 A

(b) R = 2V / 2A = 1 Ω

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