Calculate the entropy change involved in conversion of one mole (18g) of solid ice at 273 K to liquid water at the same temperature (latent heat of fusion = 6025 J mol–1).

Question

Shiksha Nation · Accepted Answer

Entropy change for ice → water is given by  Δ
  fS =Δ
    fH/Tf

Here, Δ
    fH = 6025 J mol−1, T
      f
     = 273 K       
    ∴   Δ
      fS =(6025 JK
        −1
        mol
        −1)/273 K
        
        = 22.1 JK
          −1
          mol
          −1

Calculate the entropy change involved in conversion of one mole (18g) of solid ice at 273 K to liquid water at the same temperature (latent heat of fusion = 6025 J mol^–1).

Verified Answer