Calculate the enthalpy of formation of carbon monoxide (CO) from the following data:
(i) C(s) + O2(g) → CO2(g); ΔrH° = −393.5 kJ mol−1
(ii) CO(g) + 1/2O2(g) → CO2(g); ΔrH° = −283.0 kJ mol−1
We aim at : C(s) +1/2O2(g) → CO(g); ΔfH° = ?
Subtracting equation (ii) from equation (i), we get
C(s) + 1/2 O2(g) − CO(g) → 0; ΔrH° = −393.5 − (−283.0) = −110.5 kJ mol−1
C(s) +1/2O2(g) → CO(g); ΔrH° = −110.5 kJ