A sphere of mass 40 kg is attracted by another sphere of mass 15 kg with a force of 1 / 10 mg wt. Find the value of constant of gravitation if centres of spheres are 0.2 m apart.

Question

Shiksha Nation · Accepted Answer

Given: m₁ = 40 kg, m₂ = 15 kg, r = 0.2 m

Force, F = (1/10) mg wt = (1/10 × 10⁻³) g wt = (1/10 × 10⁻⁶) kg wt = 10⁻⁷ kg wt = 9.8 × 10⁻⁷ N

[∵ 1 kg wt = 9.8 N]

As F = G (m₁m₂ / r²)

∴ G = (F r²) / (m₁m₂)

= (9.8 × 10⁻⁷ × (0.2)²) / (40 × 15)

= 6.533 × 10⁻¹¹ N·m²·kg⁻²

A sphere of mass 40 kg is attracted by another sphere of mass 15 kg with a force of 1 / 10 mg wt. Find the value of constant of gravitation if centres of spheres are 0.2 m apart.

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