A dice is tossed once. Find the probability of getting

(i) a number 5

(ii) a number greater than 5

(iii) a number less than 5

(iv) an odd number

(v) an even number

(vi) a number greater than 6

Thus, the required median = 10.

Arranging the given data in increasing order, we get:

6, 9, 10, 12, 13, 14, 18, 19, 20, 25

n = 10 (even)

Median = [(n/2)^th term + (n/2 + 1)^th term] / 2

= [(10/2)^th term + ((10/2) + 1)^th term] / 2

= [5^th term + 6^th term] / 2

= (13 + 14) / 2 = 27 / 2 = 13.5

Thus, the required median = 13.5