A 5-litre cylinder contained 10 moles of oxygen gas at 27°C. Due to sudden leakage through the hole, all the gas escaped into the atmosphere and the cylinder got empty. If the atmospheric pressure is 1.0 atmosphere, calculate the work done by the gas.
Vinitial = 5L , T = 27°C = 27 + 273K = 300K
Vfinal = nRT/P = (10 × 0.0821 × 300)/1.0= = 246.3L
ΔV = Vfinal − Vinitial = 246.3 − 5 = 241.3L
wexp = −PΔV = −1 × 241.3 L atm = −241.3 × 101.3 J = − 24443.7 J.