Write the middle term of the following: (x² − 1/x)⁶

There are 7 terms in the expansion of (x² − 1/x)⁶.

Middle term = (n + 1)/2 = (6 + 1)/2 = 4th term

We have T_r+1 = ⁿC_ra^n−rb^r

⇒ T₄ = ⁶C₃(x²)⁶⁻³(−1/x)³

= ⁶C₃(x⁶)(−1/x³) = −^6×5×4/_3×2×1x³

= −20x³

Hence, the middle term is −20x³.