Two discs have the same moment of inertia about their axis. Thicknesses are t₁ and t₂, densities are same, and R₁/R₂ = 1/4. Find t₁/t₂.
For a disc,
I = 1/2 MR²
Mass of disc:
M = ρπR²t
So,
I = 1/2 (ρπR²t)R²
I ∝ tR⁴
Since both discs have same moment of inertia,
t₁R₁⁴ = t₂R₂⁴
Given:
R₁/R₂ = 1/4
Therefore,
t₁/t₂ = (R₂/R₁)⁴
= 4⁴ = 256
Answer:
t₁/t₂ = 256