The scores of a batsman in ten innings are : 38, 70, 48, 34, 42, 55, 63, 46, 54, 44. Find the mean deviation about the median.
Arranging the data in ascending order: 34, 38, 42, 44, 46, 48, 54, 55, 63, 70
Here n = 10. Median = average of 5th and 6th observations.
Median, M = (46 + 48) / 2 = 47
Computation of Mean Deviation
| xi | |di| = |xi - 47| |
|---|---|
| 38 | 9 |
| 70 | 23 |
| 48 | 1 |
| 34 | 13 |
| 42 | 5 |
| 55 | 8 |
| 63 | 16 |
| 46 | 1 |
| 54 | 7 |
| 44 | 3 |
| Total | 86 |
Mean deviation = (1/n) Σ|di| = 86/10 = 8.6