Six point charges are kept 60° apart on a circle of radius R. Find electric field at the center.

Solution:

The charges are symmetrically placed on the circle.

Electric field due to each charge acts along the radius.

By vector addition and symmetry, horizontal components cancel partially while vertical components combine.

The resultant electric field at the center becomes:

E = -(√3 q)/(2πϵ₀R²) i

Answer:

E = -(√3 q)/(2πϵ₀R²) i