Random variable X has the given probability distribution. Find P(3 < X < 6).

Solution:

P(3 < X < 6) = P(X = 4) + P(X = 5)

From the given table:
P(X = 4) = 2k
P(X = 5) = 2k

Total probability = 1

After solving,
k = 0.055

Therefore,
P(3 < X < 6) = 2k + 2k = 4k = 4 × 0.055 = 0.22

Answer: 0.22