Evaluate:
∫020π (sin⁴x + cos⁴x) dx
Using:
sin⁴x + cos⁴x = (sin²x + cos²x)² − 2sin²x cos²x
= 1 − 2sin²x cos²x
= 1 − 1/2 sin²2x
Average value of sin²2x over a complete period is:
1/2
Therefore average value of integrand:
1 − 1/2 × 1/2 = 3/4
Length of interval:
20π
Integral:
= (3/4)(20π)
= 15π
Option (1) 15π