Potential energy is given by:

V = A√x / (x + B)

where A and B are constants.

Find the dimensions of A.

Potential energy has dimensions:

[V] = [M L² T⁻²]

Since x and B are added:

[B] = [L]

Expression:

V = A L^1/2 / L

= A L^−1/2

Therefore:

[A] = [V]L^1/2

= [M L² T⁻²] L^1/2

= [M L^5/2 T⁻²]

Final Answer

[M L^5/2 T⁻²]