Potential difference across 4Ω, 6Ω, 10Ω in series with 5V
R_total = 4+6+10 = 20Ω I = 5/20 = 0.25 A (same throughout)
|
Resistor |
V = I×R |
|---|---|
|
4Ω |
0.25 × 4 = 1 V |
|
6Ω |
0.25 × 6 = 1.5 V |
|
10Ω |
0.25 × 10 = 2.5 V |
Check: 1 + 1.5 + 2.5 = 5V