Question
GeneralGeneralGeneral

In Carius method of estimation of bromine, 1.53 g of an organic compound gives 1 g of AgBr.

Atomic masses:

  • Ag = 108
  • Br = 80

Find the percentage of bromine in the organic compound.

Verified Answer

Solution:

Molar mass of AgBr:

= 108 + 80

= 188 g mol-1

Mass of bromine present in 188 g AgBr:

= 80 g

Therefore, bromine present in 1 g AgBr:

= 80/188

= 0.4255 g

Percentage of bromine in the organic compound:

%Br = (0.4255/1.53) × 100

= 27.81%

Answer:

27.81%