In an exam, there are three papers each of 100 marks. A candidate got 53 marks in the first paper and 75 marks in the second paper. How many marks must the candidate obtain in the third paper to get an overall of 70% marks?

To solve this question, we first understand the total marks and required percentage.

Step 1: Total Marks

• 3 papers × 100 marks each = 300 total marks

Step 2: Required Marks for 70%

Required Marks = 70/100*300

So, required marks = 210

Step 3: Marks Already Obtained

• First paper = 53

• Second paper = 75

• Total so far = 53 + 75 = 128

Step 4: Marks Needed in Third Paper

• Required total = 210

• Already scored = 128

Marks needed = 210 − 128 = 82

Final Answer:

The candidate must score 82 marks in the third paper to get an overall of 70% marks.