If α and β are different complex numbers with |β| = 1, then find |(β - α/1 - ᾱβ)|
|(β - α/1 - ᾱβ)|2 = |β - α|2/|1 - ᾱβ|2
= (β - α)(β̄ - ᾱ)/(1 - ᾱβ)(1 - αβ̄) [∵ |z|2 = z z̄]
= ββ̄ - βᾱ - αβ̄ + αᾱ/1 - αβ̄ - ᾱβ + αᾱββ̄
= |β|2 - ᾱβ - αβ̄ + |α|2/1 - αβ̄ - ᾱβ + |α|2|β|2
Since |β| = 1 ⇒ |β|2 = 1,
= 1 - ᾱβ - αβ̄ + |α|2/1 - αβ̄ - ᾱβ + |α|2
= 1
∴ |(β - α/1 - ᾱβ)| = 1