If (1 + i/1 - i)m = 1, then find the least positive integral value of m.
(1 + i/1 - i)m = 1
⇒ ((1 + i)(1 + i)/(1 - i)(1 + i))m
= (1 + 2i + i2/1 - i2)m
= (1 + 2i - 1/1 + 1)m
= (2i/2)m = (i)m
So, im = 1
Now, i1 = i, i2 = -1, i3 = -i, i4 = 1
∴ m must be a multiple of 4
Therefore, the least positive integral value of m = 4