Find the value of:
(1³/1) + (1³+2³)/(1+3) + (1³+2³+3³)/(1+3+3) + ... up to 8 terms.
The nth term is:
Tn = (1³ + 2³ + 3³ + ... + n³) / (1 + 3 + 3 + ... + 3)
Using the formula:
1³ + 2³ + ... + n³ = [n(n+1)/2]²
Denominator:
1 + 3(n−1) = 3n−2
Substituting values from n = 1 to 8 and simplifying gives:
S = 72
Option (4) 72