Find the term independent of x in the expansion of (3x²/2 − 1/3x)⁹.

Let (r + 1)^th term be the term independent of x.

Then, T_r+1 = ⁹C_r(3x²/2)^9−r(−1/3x)^r

= (−1)^r × ⁹C_r × (3)^9−2r / (2)^9−r × x^18−3r

For the term to be independent of x, the power of x must be zero:

18 − 3r = 0 ⇒ r = 6

Hence, the required term = (−1)⁶ × ⁹C₆ × (3³)/(2³) = ⁹C₆ × (1)/(3³ × 2³)

= (9 × 8 × 7)/(1 × 2 × 3) × (1)/(27 × 8) = 7/18

Therefore, the term independent of x is 7/18.