Find the perimeters of 

(i) ΔABE 

(ii) the rectangle BCDE in this figure. Whose perimeter is greater?

(i) Perimeter of ΔABE = AB + BE + EA

= (5/2 + 2/3 + 3/5) = (5/2 + 11/4 + 18/5)

= (5×10/2×10 + 11×5/4×5 + 18×4/5×4)

= (50 + 55 + 72)/20 = 177/20 cm

(ii) Perimeter of rectangle = 2 (Length + Breadth)

Perimeter of rectangle = 2 [11/4 + 7/6]

= 2 [(11×3/4×3) + (7×2/6×2)] = 2 [(33 + 14)/12]

= 2 × 47/12 = 47/6 cm

Perimeter of ΔABE = 177/20 cm

Changing them to like fractions, we obtain

177/20 × 3/3 = 531/60

47/6 × 10/10 = 470/60

As 531 > 470,

177/20 > 47/6

Perimeter (ΔABE) > Perimeter (BCDE)