find limx → 1 f(x), where f(x) = {x2 - 1, x ≤ 1 -x2 - 1, x 1

Question

find limx → 1 f(x), where f(x) = {x2 - 1, x ≤ 1 -x2 - 1, x > 1

Shiksha Nation · Accepted Answer

limx → 1- f(x) = limx → 1- [x2 - 1] = 12 - 1 = 1 - 1 = 0limx → 1+ f(x) = limx → 1 [-x2 - 1] = -12 - 1 = -1 - 1 = -2It is observed that limx → 1- f(x) ≠ limx → 1+ f(x).Hence, limx → 1 f(x) does not exist.

find lim_{x → 1} f(x), where f(x) = {x² - 1, x ≤ 1 -x² - 1, x > 1

Verified Answer

find lim_{x → 1} f(x), where f(x) = {x² - 1, x ≤ 1 -x² - 1, x > 1

Verified Answer