Evaluate:limx→1 [(x - 2)/(x2 - x) - 1/(x3 - 3x2 + 2x)]

Question

Shiksha Nation · Accepted Answer

[ (x - 2)/x(x - 1) - 1/x(x - 1)(x - 2) ]= (x² - 4x + 4 - 1)/x(x - 1)(x - 2)= (x² - 4x + 3)/x(x - 1)(x - 2)⇒ limx→1 (x² - 4x + 3)/x(x - 1)(x - 2)= limx→1 (x - 3)(x - 1)/x(x - 1)(x - 2)= limx→1 (x - 3)/x(x - 2)= (1 - 3)/1(1 - 2)= 2

Evaluate:
lim_x→1 [^{(x - 2)}/_{(x² - x)} - ¹/_{(x³ - 3x² + 2x)}]

Verified Answer

Evaluate:
lim_x→1 [^{(x - 2)}/_{(x² - x)} - ¹/_{(x³ - 3x² + 2x)}]

Verified Answer