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Evaluate: limx→π/2 [(1 - sin x) / cos x]
limx→π/2 [(1 - sin x) / cos x]
= limy→0 [(1 - sin(π/2 - y)) / cos(π/2 - y)] (taking π/2 - x = y)
= limy→0 [(1 - cosy) / siny]
= limy→0 [(2sin2(y/2)) / (2sin(y/2) cos(y/2))]
= limy→0 tan(y/2)
= 0