As shown in the figure, two blocks of 4 kg and one block of 6 kg are connected through a pulley system. Find the ratio T₁/T₂.
The arrangement consists of an Atwood machine where the left side has a 4 kg block and the right side effectively carries a 4 kg block connected to a 6 kg block.
Total mass on the right side:
4 + 6 = 10 kg
Let acceleration of the system be a.
For the left 4 kg block moving upward:
T₁ − 4g = 4a
Therefore:
T₁ = 4g + 4a
For the combined right side:
10g − T₁ = 10a
Substituting T₁:
10g − (4g + 4a) = 10a
6g = 14a
a = 3g/7
Now:
T₁ = 4g + 4(3g/7)
T₁ = 40g/7
For the 6 kg block:
6g − T₂ = 6a
Substituting a = 3g/7:
6g − T₂ = 18g/7
T₂ = 24g/7
Therefore:
T₁/T₂ = (40g/7)/(24g/7)
T₁/T₂ = 40/24
T₁/T₂ = 5/3
Hence, the required ratio is:
T₁/T₂ = 5/3