Question
Class 7MathematicsData Handling Class 7

A dice is tossed once. Find the probability of getting

(i) a number 5

(ii) a number greater than 5

(iii) a number less than 5

(iv) an odd number

(v) an even number

(vi) a number greater than 6

Verified Answer

Total number of outcomes = 6

n(S) = 6

(i) An event of getting a number 5

n(E) = 1

Probability =n(E)/n(S) =1/6

(ii) An event of getting a number 5 greater than 5, i.e., 6

n(E) = 1

Probability =n(E)/n(S) =1/6

(iii) An event of getting a number less than 5, i.e., 1, 2, 3 and 4.

n(E) = 4

Probability =n(E)/n(S) =4/6=2/3

(iv) An event of getting an odd number, i.e., 1, 3 and 5.

n(E) = 3

Probability =n(E)/n(S) =3/6=1/2

(v) An event of getting an even number, i.e., 2, 4 and 6.

n(E) = 3

Probability =n(E)/n(S) =3/6=1/2

(vi) An event of getting a number greater than 6, i.e., Nil.

n(E) = 0

Probability =n(E)/n(S) =0/6= 0