A dibromo compound C₉H₁₀Br₂ reacts with sodamide followed by dilute HCl and later with mercuric sulphate and sulphuric acid. Final product gives positive iodoform test and negative Tollens test. Identify compound P.

Solution:

Dibromo compound on treatment with sodamide forms an alkyne.

Hydration of alkyne using HgSO₄/H₂SO₄ gives ketone.

Positive iodoform test indicates presence of CH₃CO− group.

Negative Tollens test confirms compound is not an aldehyde.

Hence final compound is methyl ketone:

C₆H₅COCH₃

Answer: Acetophenone (1-Phenylethanone)