Question
GeneralGeneralGeneral

A 7.9 MeV alpha particle scatters from a target of atomic number 79. Estimate the distance of closest approach.

Verified Answer

Formula:

r = (1 / 4πε₀) × (Z₁Z₂e² / E)

Given:

  • Z₁ = 2 for alpha particle
  • Z₂ = 79
  • Energy = 7.9 MeV

After substitution,

Answer:

2.88 × 10-14 m