5.8 g aniline is converted into benzanilide. If percentage yield is 82%, find the mass of benzanilide formed.

Solution:

Reaction:

C₆H₅NH₂ → Benzanilide

Molar mass of aniline = 93 g/mol

Moles of aniline:

= 5.8 / 93

= 0.0624 mol

Molar mass of benzanilide = 197 g/mol

Theoretical mass of benzanilide:

= 0.0624 × 197

= 12.29 g

Actual yield:

= 12.29 × 82 / 100

= 10.08 g

Answer: Mass of benzanilide formed = 10.08 g