100 g of 98% H₂SO₄ solution is mixed with 100 g of 49% H₂SO₄ solution. Find mole fraction of H₂SO₄.

Solution:

Amount of H₂SO₄ in first solution = 98% of 100 g = 98 g

Amount of water in first solution = 100 - 98 = 2 g

Amount of H₂SO₄ in second solution = 49% of 100 g = 49 g

Amount of water in second solution = 100 - 49 = 51 g

Total H₂SO₄ = 98 + 49 = 147 g

Total water = 2 + 51 = 53 g

Moles of H₂SO₄ = 147 / 98 = 1.5 mol

Moles of water = 53 / 18 = 2.94 mol

Total moles = 1.5 + 2.94 = 4.44 mol

Mole fraction of H₂SO₄ = 1.5 / 4.44 = 0.338

Answer: Mole fraction of H₂SO₄ = 0.338